x^2=23/3

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Solution for x^2=23/3 equation:



x^2=23/3
We move all terms to the left:
x^2-(23/3)=0
We add all the numbers together, and all the variables
x^2-(+23/3)=0
We get rid of parentheses
x^2-23/3=0
We multiply all the terms by the denominator
x^2*3-23=0
Wy multiply elements
3x^2-23=0
a = 3; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·3·(-23)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{69}}{2*3}=\frac{0-2\sqrt{69}}{6} =-\frac{2\sqrt{69}}{6} =-\frac{\sqrt{69}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{69}}{2*3}=\frac{0+2\sqrt{69}}{6} =\frac{2\sqrt{69}}{6} =\frac{\sqrt{69}}{3} $

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